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| Dropdownlist Rendering error PLEASE HELP |
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This message was discovered on ASPFriends.com 'aspngdatagridrepeaterdatalist' list.
| Wolfgang Baeck |
| GOOD ANSWER |
Hi,
This seems to be too simple, but I have a real problem with it. The rendering of the webpage complains with:
A DropDownList cannot have multiple items selected
and I have only one item selected!
I have many other pages with DDLs that are working and I just created another one and I get the same error there too. Darn it, I know how to use DDL's, what is going on?
I have a webpage where I have the ability to select an item from a grid, and then, in the postback, I display the details for that item for edit. One of the widgets is a dropdownlist. Whenever I select an Item in the grid that causes a different item to be selected than which was previously selected in the dropdownlist, I get the error:
A DropDownList cannot have multiple items selected
I only select one item , albeit a different one than that which was selected before. The code behind section that selects the item gives no error, only the rendering Do I have to clear the selection of the list first? If so, how and why only on this page?
Here is the section:
private void user_Select(object sender,System.Web.UI.WebControls.DataGridCommandEventArgs e) { string user = e.CommandArgument.ToString(); HopeAndHome.Components.User aUser = new HopeAndHome.Components.User(); aUser.sUser = user; DataTable aUserTable = aUser.Select(); if (aUserTable.Rows.Count > 0) { lblUser.Text = user; btnRemoveUser.Visible = true; btnUpdate.Visible = true; btnDeleteLog.Visible = true; DataRow myRow = aUserTable.Rows[0]; int id = (int)myRow["Person_LegalEntity_Id"]; lblLegalEntityId.Text = id.ToString(); UserLog1.iLegalEntityId = id; UserLog1.Visible = true; txtUser.Text = (string)myRow["User"]; txtPassword.Text = (string)myRow["Password"]; txtFullName.Text = (string)myRow["LastName"] + ", " + (string)myRow["FirstName"];
ddlRole.Items.FindByValue((string)myRow["Role"]).Selected = true; } }
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| Ben Miller |
| GOOD ANSWER |
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| Wolfgang Baeck |
| GOOD ANSWER |
This is a multi-part message in MIME format.
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[aspngdatagridrepeaterdatalist] Dropdownlist Rendering error PLEASE = HELPHi Ben,
Thanks for even thinking about it. I have this posted now 4 times and no = success.
It didn't work. I'm also not sure how this would result in a previous = selection being "undone" and why my original solution works in some = cases.
Wolfgang -----Original Message----- From: Ben Miller [mailto:Click here to reveal e-mail address] Sent: Tuesday, July 23, 2002 3:25 PM To: aspngDataGridRepeaterDatalist Subject: RE: [aspngdatagridrepeaterdatalist] Dropdownlist Rendering = error PLEASE HELP
Your problem could be that instead of setting the SelectedIndex of the = DDL, you are trying to make the Selected property True.
So I would suggest instead of doing it the way you are, to change it = around and use the SelectedIndex property.
ddlRole.Items.FindByValue((string)myRow["Role"]).Selected =3D true;
Instead:
ListItem objItem =3D ddlRole.Items.FindByValue((string)myRow["Role"]); ddlRole.SelectedIndex =3D ddlRole.Items.IndexOf(objItem);
Ben. -----Original Message-----=20 From: Wolfgang Baeck [mailto:Click here to reveal e-mail address]=20 Sent: Tue 7/23/2002 10:26 AM=20 To: aspngDataGridRepeaterDatalist=20 Cc:=20 Subject: [aspngdatagridrepeaterdatalist] Dropdownlist Rendering = error PLEASE HELP
Hi,
This seems to be too simple, but I have a real problem with it. The rendering of the webpage complains with:
A DropDownList cannot have multiple items selected
and I have only one item selected!
I have many other pages with DDLs that are working and I just = created another one and I get the same error there too. Darn it, I know how = to use DDL's, what is going on?
I have a webpage where I have the ability to select an item from a = grid, and then, in the postback, I display the details for that item for edit. = One of the widgets is a dropdownlist. Whenever I select an Item in the grid = that causes a different item to be selected than which was previously = selected in the dropdownlist, I get the error:
A DropDownList cannot have multiple items selected
I only select one item , albeit a different one than that which was = selected before. The code behind section that selects the item gives no = error, only the rendering Do I have to clear the selection of the list first? If = so, how and why only on this page?
Here is the section:
private void user_Select(object sender,System.Web.UI.WebControls.DataGridCommandEventArgs e) { string user =3D = e.CommandArgument.ToString(); HopeAndHome.Components.User aUser =3D new HopeAndHome.Components.User(); aUser.sUser =3D user; DataTable aUserTable =3D aUser.Select(); if (aUserTable.Rows.Count > 0) { lblUser.Text =3D user; btnRemoveUser.Visible =3D true; btnUpdate.Visible =3D true; btnDeleteLog.Visible =3D true; DataRow myRow =3D = aUserTable.Rows[0]; int id =3D (int)myRow["Person_LegalEntity_Id"]; lblLegalEntityId.Text =3D = id.ToString(); UserLog1.iLegalEntityId =3D id; UserLog1.Visible =3D true; txtUser.Text =3D = (string)myRow["User"]; txtPassword.Text =3D (string)myRow["Password"]; txtFullName.Text =3D = (string)myRow["LastName"] + ", " + (string)myRow["FirstName"];
ddlRole.Items.FindByValue((string)myRow["Role"]).Selected =3D true; } }
| [aspngdatagridrepeaterdatalist] member Click here to reveal e-mail address =3D = YOUR ID | = http://www.aspfriends.com/aspfriends/aspngdatagridrepeaterdatalist.asp = =3D JOIN/QUIT
------=_NextPart_001_000F_01C23276.79B06BD0 Content-Type: text/html; charset="utf-8" Content-Transfer-Encoding: quoted-printable
=EF=BB=BF<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN"> <HTML><HEAD><TITLE>[aspngdatagridrepeaterdatalist] Dropdownlist = Rendering error PLEASE HELP</TITLE> <META http-equiv=3DContent-Type content=3D"text/html; charset=3Dutf-8"> <META content=3D"MSHTML 6.00.2600.0" name=3DGENERATOR></HEAD> <BODY dir=3Dltr> <DIV><SPAN class=3D542042000-24072002><FONT face=3DArial color=3D#0000ff = size=3D2>Hi=20 Ben,</FONT></SPAN></DIV> <DIV><SPAN class=3D542042000-24072002><FONT face=3DArial color=3D#0000ff =
size=3D2></FONT></SPAN> </DIV> <DIV><SPAN class=3D542042000-24072002><FONT face=3DArial color=3D#0000ff = size=3D2>Thanks=20 for even thinking about it. I have this posted now 4 times and no=20 success.</FONT></SPAN></DIV> <DIV><SPAN class=3D542042000-24072002><FONT face=3DArial color=3D#0000ff =
size=3D2></FONT></SPAN> </DIV> <DIV><SPAN class=3D542042000-24072002><FONT face=3DArial color=3D#0000ff = size=3D2>It=20 didn't work. I'm also not sure how this would result in a previous = selection=20 being "undone" and why my original solution works in some=20 cases.</FONT></SPAN></DIV> <DIV><SPAN class=3D542042000-24072002><FONT face=3DArial color=3D#0000ff =
size=3D2></FONT></SPAN> </DIV> <DIV><SPAN class=3D542042000-24072002><FONT face=3DArial color=3D#0000ff =
size=3D2>Wolfgang</FONT></SPAN></DIV> <BLOCKQUOTE dir=3Dltr style=3D"MARGIN-RIGHT: 0px"> <DIV class=3DOutlookMessageHeader dir=3Dltr align=3Dleft><FONT = face=3DTahoma=20 size=3D2>-----Original Message-----<BR><B>From:</B> Ben Miller=20 [mailto:Click here to reveal e-mail address]<BR><B>Sent:</B> Tuesday, July 23, 2002 = 3:25=20 PM<BR><B>To:</B> aspngDataGridRepeaterDatalist<BR><B>Subject:</B> RE:=20 [aspngdatagridrepeaterdatalist] Dropdownlist Rendering error PLEASE=20 HELP<BR><BR></FONT></DIV> <DIV>Your problem could be that instead of setting the SelectedIndex = of the=20 DDL, you are trying to make the Selected property True.</DIV> <DIV> </DIV> <DIV>So I would suggest instead of doing it the way you are, to change = it=20 around and use the SelectedIndex property.</DIV> <DIV> </DIV> <DIV><FONT = size=3D2>ddlRole.Items.FindByValue((string)myRow["Role"]).Selected =3D=20 true;</FONT><BR></DIV> <DIV>Instead:</DIV> <DIV> </DIV> <DIV>ListItem objItem =3D=20 ddlRole.Items.FindByValue((string)myRow["Role"]);</DIV> <DIV>ddlRole.SelectedIndex =3D ddlRole.Items.IndexOf(objItem);</DIV> <DIV> </DIV> <DIV>Ben.</DIV> <BLOCKQUOTE dir=3Dltr style=3D"MARGIN-RIGHT: 0px"> <DIV><FONT size=3D2>-----Original Message----- <BR><B>From:</B> = Wolfgang Baeck=20 [mailto:Click here to reveal e-mail address] <BR><B>Sent:</B> Tue 7/23/2002 10:26 = AM=20 <BR><B>To:</B> aspngDataGridRepeaterDatalist <BR><B>Cc:</B>=20 <BR><B>Subject:</B> [aspngdatagridrepeaterdatalist] Dropdownlist = Rendering=20 error PLEASE HELP<BR><BR></FONT></DIV> <P><FONT size=3D2>Hi,<BR><BR>This seems to be too simple, but I have = a real=20 problem with it. The<BR>rendering of the webpage complains = with:<BR><BR>A=20 DropDownList cannot have multiple items selected<BR><BR>and I have = only one=20 item selected!<BR><BR>I have many other pages with DDLs that are = working and=20 I just created<BR>another one and I get the same error there too. = Darn it, I=20 know how to use<BR>DDL's, what is going on?<BR><BR>I have a webpage = where I=20 have the ability to select an item from a grid, and<BR>then, in the=20 postback, I display the details for that item for edit. One = of<BR>the=20 widgets is a dropdownlist. Whenever I select an Item in the grid=20 that<BR>causes a different item to be selected than which was = previously=20 selected in<BR>the dropdownlist, I get the error:<BR><BR>A = DropDownList=20 cannot have multiple items selected<BR><BR>I only select one item , = albeit a=20 different one than that which was selected<BR>before. The code = behind=20 section that selects the item gives no error, only<BR>the rendering = Do I=20 have to clear the selection of the list first? If so,<BR>how and why = only on=20 this page?<BR><BR>Here is the=20 = section:<BR><BR> &nb= sp; =20 private void=20 = user_Select(object<BR>sender,System.Web.UI.WebControls.DataGridCommandEve= ntArgs=20 = e)<BR> &= nbsp; =20 = {<BR> &n= bsp; =20 string user =3D=20 = e.CommandArgument.ToString();<BR> &nbs= p;  = ; =20 HopeAndHome.Components.User aUser =3D=20 = new<BR>HopeAndHome.Components.User();<BR> &n= bsp; &nb= sp; =20 aUser.sUser =3D=20 = user;<BR> &nbs= p;  = ;=20 DataTable aUserTable =3D=20 = aUser.Select();<BR> = &= nbsp; =20 if (aUserTable.Rows.Count >=20 = 0)<BR> &= nbsp; =20 = {<BR> &n= bsp; &nb= sp; =20 lblUser.Text =3D=20 = user;<BR> &nbs= p;  = ; =20 btnRemoveUser.Visible =3D=20 = true;<BR> &nbs= p;  = ; =20 btnUpdate.Visible =3D=20 = true;<BR> &nbs= p;  = ; =20 btnDeleteLog.Visible =3D=20 = true;<BR> &nbs= p;  = ; =20 DataRow myRow =3D=20 = aUserTable.Rows[0];<BR> &n= bsp; &nb= sp; =20 int id=20 = =3D<BR>(int)myRow["Person_LegalEntity_Id"];<BR> &n= bsp; &nb= sp; &nbs= p; =20 lblLegalEntityId.Text =3D=20 = id.ToString();<BR> &= nbsp; &n= bsp; =20 UserLog1.iLegalEntityId =3D=20 = id;<BR> = &= nbsp; =20 UserLog1.Visible =3D=20 = true;<BR> &nbs= p;  = ; =20 txtUser.Text =3D=20 = (string)myRow["User"];<BR>  = ; = =20 txtPassword.Text=20 = =3D<BR>(string)myRow["Password"];<BR> = &= nbsp; &n= bsp;=20 txtFullName.Text =3D (string)myRow["LastName"]<BR>+ ", " +=20 = (string)myRow["FirstName"];<BR><BR>ddlRole.Items.FindByValue((string)myRo= w["Role"]).Selected=20 =3D=20 = true;<BR> &nbs= p;  = ;=20 = }<BR> &n= bsp; =20 }<BR><BR><BR>| [aspngdatagridrepeaterdatalist] member = Click here to reveal e-mail address =3D=20 YOUR ID<BR>| <A=20 = href=3D"http://www.aspfriends.com/aspfriends/aspngdatagridrepeaterdatalis= t.asp">http://www.aspfriends.com/aspfriends/aspngdatagridrepeaterdatalist= .asp</A>=20 =3D JOIN/QUIT<BR></FONT></P></BLOCKQUOTE></BLOCKQUOTE></BODY></HTML>
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| Hidayath Aman |
| GOOD ANSWER |
Do a ClearSelection() , before using the set it will fix the problem (Type your message here)
-------------------------------- From: Hidayath Aman
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| Tiago D'Herbe |
| GOOD ANSWER |
Hello everyone,
i haven't tried the ClearSelection() Method, but i had many problems with this DDL issue, though using the SelectedIndex it worked on all cases.
best regards
-------------------------------- From: Tiago D'Herbe
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| Vijay Agrawal |
| GOOD ANSWER |
(Type your message here)
-------------------------------- From: Vijay Agrawal
Try using, DDL.ClearSelection()
Vijay
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BootFX
Reliable and powerful .NET application framework. |
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