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replacing \n

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dave wanta (VIP)

hi all,
Does anyone know the RegEx that would replace all instances of \n where there ISN'T a \r\n ?

Basically I want to make sure every \n is actually \r\n, but I need to make sure I don't end up with \r\n\n.

Make sense?

Thanks,
Dave

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Wayne King (ASP.NET)

This is a multi-part message in MIME format.

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Try this (using C# syntax):
sResult =3D Regex.Replace(sInput, @"(?<!\r)\n", @"\r\n");
=20
It seems like these would be less efficient:
sResult =3D Regex.Replace(sInput, @"([^\r]|^)\n", @"$1\r\n");
sResult =3D Regex.Replace(sInput, @"^\n|([^\r])\n", @"$1\r\n");
=20
=20
-Wayne=20
This posting is provided "AS IS" with no warranties, and confers no
rights.=20
=20
-----Original Message-----
From: dave wanta [mailto:Click here to reveal e-mail address]=20
Sent: Wednesday, July 17, 2002 4:00 PM
To: aspngregexp
Subject: [aspngregexp] replacing \n

hi all,
Does anyone know the RegEx that would replace all instances of \n where
there ISN'T a \r\n ?
=20
Basically I want to make sure every \n is actually \r\n, but I need to
make sure I don't end up with \r\n\n.
=20
Make sense?
=20
Thanks,
Dave

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<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<HTML><HEAD><TITLE>Message</TITLE>
<META http-equiv=3DContent-Type content=3D"text/html; =
charset=3Dus-ascii">
<META content=3D"MSHTML 6.00.2716.2200" name=3DGENERATOR>
<STYLE></STYLE>
</HEAD>
<BODY bgColor=3D#ffffff>
<DIV><FONT face=3D"Bookman Old Style" color=3D#008000 size=3D2><SPAN=20
class=3D862533716-18072002>Try this (using C# =
syntax):</SPAN></FONT></DIV>
<DIV><FONT face=3D"Courier New" size=3D2><SPAN=20
class=3D862533716-18072002>    sResult =3D =
Regex.Replace(sInput,=20
@"(?<!\r)\n", @"\r\n");</SPAN></FONT></DIV>
<DIV><FONT face=3D"Bookman Old Style" color=3D#008000 size=3D2><SPAN=20
class=3D862533716-18072002></SPAN></FONT> </DIV>
<DIV><FONT face=3D"Bookman Old Style" color=3D#008000 size=3D2><SPAN=20
class=3D862533716-18072002>It seems like these would be less=20
efficient:</SPAN></FONT></DIV>
<DIV><FONT face=3D"Bookman Old Style" color=3D#008000 size=3D2><SPAN=20
class=3D862533716-18072002>
<DIV><FONT face=3D"Courier New" color=3D#000000 size=3D2><SPAN=20
class=3D862533716-18072002>    sResult =3D =
Regex.Replace(sInput,=20
@"([^\r]|^)\n", @"$1\r\n");</SPAN></FONT></DIV></SPAN></FONT></DIV>
<DIV><FONT face=3D"Bookman Old Style" color=3D#008000 size=3D2>
<DIV><FONT face=3D"Courier New" color=3D#000000 size=3D2><SPAN=20
class=3D862533716-18072002>    sResult =3D =
Regex.Replace(sInput,=20
@"^\n|([^\r])\n", @"$1\r\n");</SPAN></FONT></DIV></FONT></DIV>
<DIV><SPAN lang=3Den-us><FONT face=3D"Courier New" =
size=3D2></FONT></SPAN> </DIV>
<DIV><SPAN lang=3Den-us><FONT face=3D"Courier New" =
size=3D2></FONT></SPAN> </DIV>
<DIV><SPAN lang=3Den-us><FONT face=3D"Courier New" =
size=3D2>-Wayne</FONT></SPAN>=20
<BR><SPAN lang=3Den-us><FONT face=3D"Courier New" size=3D2> This =
posting is=20
provided "AS IS" with no warranties, and confers no =
rights.</FONT></SPAN> </DIV>
<DIV><FONT face=3D"Courier New" size=3D2></FONT> </DIV>
<DIV></DIV>
<DIV class=3DOutlookMessageHeader lang=3Den-us dir=3Dltr =
align=3Dleft><FONT face=3DTahoma=20
size=3D2>-----Original Message-----<BR><B>From:</B> dave wanta=20
[mailto:Click here to reveal e-mail address] <BR><B>Sent:</B> Wednesday, July 17, 2002 =
4:00=20
PM<BR><B>To:</B> aspngregexp<BR><B>Subject:</B> [aspngregexp] replacing=20
\n<BR><BR></FONT></DIV>
<DIV><FONT face=3DArial size=3D2>hi all,</FONT></DIV>
<DIV><FONT face=3DArial size=3D2>Does anyone know the RegEx that =
would replace=20
all instances of \n where there ISN'T a \r\n ?</FONT></DIV>
<DIV><FONT face=3DArial size=3D2></FONT> </DIV>
<DIV><FONT face=3DArial size=3D2>Basically I want to make sure =
every \n is=20
actually \r\n, but I need to make sure I don't end up with =
\r\n\n.</FONT></DIV>
<DIV><FONT face=3DArial size=3D2></FONT> </DIV>
<DIV><FONT face=3DArial size=3D2>Make sense?</FONT></DIV>
<DIV><FONT face=3DArial size=3D2></FONT> </DIV>
<DIV><FONT face=3DArial size=3D2>Thanks,</FONT></DIV>
<DIV><FONT face=3DArial size=3D2>Dave</FONT></DIV></BODY></HTML>
=00
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